The potentiometer- Comparison of emf
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1. In a potentiometer experiment to compare the emf's of two primary cells, the balancing points obtained as l1 and l2 respectively. If E2 be the emf of the second cell, what is the emf E1 of the other cell?
E1 = (l1×l2)/E2
E1 = (E2×l1)/l2
E1 = (E2×l2)/l1
Data inadequate
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